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#include <stdio.h>
/* The C Programming Language: 2nd Edition
*
* Exercise 1-22: Write a program to 'fold' long input lines into two or more
* shorter lines after the last non-blank character that occurs before the n-th
* column of input. Make sure your program does something intelligent with very
* long lines, and if there are no blanks or tabs before the specified column.
*
* Answer: So... Quite a hefty requirement. In a nutshell, our goal is to
* create line-wrapping. The simplest approach is to take every character until
* EOF, like a stream. Spaces and tabs need special treatment. If your input
* isn't a newline or a blank, it will just be printed. Spaces and tabs only
* print if the next non-blank is before the end of the line length limit. To
* make things prettier, I opted to ignore leading whitespace as well.
*
*/
#define LINEWIDTH 20
int main() {
int c, tmp, ts;
int spaces = 0;
int col = 0;
printf("Just type. It'll wrap to %d characters per line.\n", LINEWIDTH);
while ((c = getchar()) != EOF) {
if (col >= LINEWIDTH) {
putchar('\n');
col = 0;
}
if (c == ' ') {
if (col == 0) {
continue;
}
spaces = 1;
while ((tmp = getchar()) == ' ') {
spaces++;
}
if (col + spaces < LINEWIDTH) {
while (spaces > 0) {
putchar(' ');
col++;
spaces--;
}
} else {
putchar('\n');
col = 0;
}
putchar(tmp);
col++;
continue;
}
/* There's some duplicated effort in here, but I couldn't find a cleaner
* way to put tab stuff in with the spaces, where it belongs */
if (c == '\t') {
if (col == 0) {
continue;
}
spaces = 1;
while ((tmp = getchar()) == '\t') {
spaces++;
}
ts = (spaces * 8) - (col % 8);
if (col + ts < LINEWIDTH) {
spaces = (spaces * 8) - (col % 8);
while (spaces > 0) {
putchar(' ');
spaces--;
col++;
}
} else {
putchar('\n');
col = 0;
}
putchar(tmp);
col++;
continue;
}
putchar(c);
col++;
if (c == '\n') {
col = 0;
}
}
return 0;
}
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