blob: cbaced6615a92a40004b7405cb46461608d37aac (
plain)
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
|
#include <stdio.h>
/* The C Programming Language: 2nd Edition
*
* Exercise 1-17: Write a program to print all input lines that are longer
* than 80 characters.
*
* Answer: Let's build on the buffering idea from Exercise 1-16 and narrow
* it to lines over 80 characters long.
*/
#define MINLENGTH 80
int main() {
/* longline is used as a boolean that tells us if it's a line worth printing */
int longline = 0;
/* len is simply a character counter, while c is the character itself. */
int len, c;
char buffer[MINLENGTH];
while ((c = getchar()) != EOF) {
buffer[len] = c;
/* When we meet the end of the line, we need to print the rest of the line,
* but only if we're already in a long line. Otherwise, reset our state.
*/
if (c == '\n') {
if (longline == 1 && len < MINLENGTH - 1) {
buffer[len + 1] = '\0';
printf("%-s", buffer);
}
len = 0;
longline = 0;
continue;
}
/* When the buffer has filled up, output its contents! */
if (len == MINLENGTH) {
buffer[len + 1] = '\0';
printf("%-s", buffer);
len = 0;
longline = 1;
continue;
}
/* If neither of the above cases are caught, increment our counter and fetch
more data.
*/
++len;
}
return 0;
}
|
