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#include <stdio.h>
/* The C Programming Language: 2nd Edition
*
* Exercise 1-14: Write a program to print a histogram of the frequencies of
* different characters in its input.
*
* Answer: Using an array of characters (hint: that's what a string is) with
* an array of ints is a good way to pair them up for counting. The 'i'
* iterator variable ties to both so that lengths[i] represents the count for
* chars[i].
*/
int main(void) {
/* Rundown of variables:
c = current input char
ltrs = letter count
chars = string containing the characters the program will count
lengths = the counts for each character
*/
int c;
int i = 0;
char chars[] = "0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ";
/* cnum is the number of characters found in the above string */
int cnum = 0;
while (chars[i] != '\0') {
cnum += 1;
++i;
}
/* This array need its members to be initialized to zero. */
int lengths[cnum];
for (i = 0; i <= cnum; ++i) {
lengths[i] = 0;
}
// Capture input until it ends
while ((c = getchar()) != EOF) {
for (i = 0; i < cnum; ++i) {
if (c == chars[i]) {
lengths[i] += 1;
}
}
}
// This is ugly and I wish I knew a better way to do it.
printf("\nCHARACTER FREQUENCY\n\n 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75\n");
int iter = 0;
while (iter <= cnum) {
i = lengths[iter];
if (i > 0) {
printf("%2c | ", chars[iter]);
while (i > 0) {
printf("#");
i -= 1;
}
printf("\n");
}
++iter;
}
return 0;
}
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