1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
|
#include <stdio.h>
#define IN 1
#define OUT 0
#define MINWLENGTH 2
#define MAXWLENGTH 20
int main(void) {
/* Rundown of variables:
c = current input char
state = inside or outside a word
ltrs = letter count
wrds = word count
lines = you should be shot if you don't know
lengths = an array that keeps track of how often words up to x chars long
occur.
*/
int c, state, ltrs, wrds, lines, wlen;
int lengths[MAXWLENGTH];
int i;
for (i = 0; i <= MAXWLENGTH; ++i) {
lengths[i] = 0;
}
ltrs = wrds = wlen = 0;
lines = 1;
state = OUT;
// Capture input until it ends
while ((c = getchar()) != EOF) {
// If it's whitespace, we've exited a word
if (c == '\n' || c == ' ' || c == '\t') {
if (state == IN) {
++wrds; // ...and should increase the count.
state = OUT;
/* Check to see if the word is eligible to be counted. */
if (wlen <= MAXWLENGTH) {
++lengths[wlen];
}
// Reset our word length now.
wlen = 0;
}
/* If it's a new line, we're still out of a word but need to increment the
line count */
if (c == '\n') {
++lines;
}
} else {
/* If nothing else, we know it's just a random character or a letter. */
state = IN;
++wlen;
}
/* Everything that's input counts as a letter. */
++ltrs;
}
// This is ugly and I wish I knew a better way to do it.
printf("\nWORD LENGTH FREQUENCY\n\n 5 10 15 20 25 30 35 40 45 50 55 60 65 70 75\n");
int iter;
iter = MINWLENGTH;
while (iter <= MAXWLENGTH) {
i = lengths[iter];
if (i > 0) {
printf("%2d | ", iter);
while (i > 0) {
printf("#");
i = i-1;
}
printf("\n");
}
++iter;
}
printf("%d words, %d chars, %d lines.\n", wrds, ltrs, lines);
return 0;
}
|
