aboutsummaryrefslogtreecommitdiff
diff options
context:
space:
mode:
-rw-r--r--1-01_hello-world.c14
-rw-r--r--1-02_escape-sequences.c15
-rw-r--r--1-03_temp-table-header.c29
-rw-r--r--1-04_celsius_converter.c27
-rw-r--r--1-05_backwards-table.c29
-rw-r--r--1-06_eof-test.c15
-rw-r--r--1-07_eof-value.c13
-rw-r--r--1-08_space-counter.c29
-rw-r--r--1-09_single-spacing.c27
-rw-r--r--1-10_literal-escapes.c33
-rw-r--r--1-11_word-count.c37
-rw-r--r--1-12_one-word-per-line.c39
12 files changed, 307 insertions, 0 deletions
diff --git a/1-01_hello-world.c b/1-01_hello-world.c
new file mode 100644
index 0000000..e02c87a
--- /dev/null
+++ b/1-01_hello-world.c
@@ -0,0 +1,14 @@
+#include <stdio.h>
+
+/* The C Programming Language, 2nd Edition
+ *
+ * Exercise 1-1: Run the "hello, world" program on your system. Experiment with
+ * leaving out parts of the program, to see what error messages you get.
+ *
+ * This is the typical first exercise. No need for me to putz with it.
+ */
+
+int main(void) {
+ printf("Hello world!\n");
+ return 0;
+}
diff --git a/1-02_escape-sequences.c b/1-02_escape-sequences.c
new file mode 100644
index 0000000..8d122e0
--- /dev/null
+++ b/1-02_escape-sequences.c
@@ -0,0 +1,15 @@
+#include <stdio.h>
+
+/* The C Programming Language, 2nd Edition
+ *
+ * Exercise 1-2: Experiment to find out what happens when printf()'s argument
+ * string contains \c, where 'c' is some character that's not \, t, b, n, or ".
+ *
+ * Answer: This file will not (normally) compile because \d is not a valid
+ * escape sequence. Your compiler may ignore this, however.
+ */
+
+int main(void) {
+ printf("Hello world! \d\n");
+ return 0;
+}
diff --git a/1-03_temp-table-header.c b/1-03_temp-table-header.c
new file mode 100644
index 0000000..d0d069c
--- /dev/null
+++ b/1-03_temp-table-header.c
@@ -0,0 +1,29 @@
+#include <stdio.h>
+
+/* The C Programming Language, 2nd Edition
+ *
+ * Exercise 1-3: Modify the temperature conversion program to print a heading
+ * above the table.
+ *
+ * Answer: Just add a printf() or two before the table.
+ */
+
+int main(void) {
+ float fahr, celsius;
+ int lower, upper, step;
+
+ lower = 0;
+ upper = 300;
+ step = 20;
+
+ fahr = lower;
+
+ printf(" F | C\n");
+ printf("------------\n");
+ while (fahr <= upper) {
+ celsius = (5.0 / 9.0) * (fahr - 32.0);
+ printf(" %3.0f %6.1f\n", fahr, celsius);
+ fahr += step;
+ }
+ return 0;
+}
diff --git a/1-04_celsius_converter.c b/1-04_celsius_converter.c
new file mode 100644
index 0000000..a397d9a
--- /dev/null
+++ b/1-04_celsius_converter.c
@@ -0,0 +1,27 @@
+#include <stdio.h>
+
+/* The C Programming Language, 2nd Edition
+ *
+ * Exercise 1-4: Write a program to print the corresponding Celsius to
+ * Fahrenheit table.
+ */
+
+int main(void) {
+ float fahr, celsius;
+ int lower, upper, step;
+
+ lower = 0;
+ upper = 300;
+ step = 20;
+
+ celsius = lower;
+
+ printf(" C | F\n");
+ printf("------------\n");
+ while (celsius <= upper) {
+ fahr = (celsius * (9.0 / 5.0)) + 32.0;
+ printf(" %3.0f %6.1f\n", celsius, fahr);
+ celsius += step;
+ }
+ return 0;
+}
diff --git a/1-05_backwards-table.c b/1-05_backwards-table.c
new file mode 100644
index 0000000..a09619a
--- /dev/null
+++ b/1-05_backwards-table.c
@@ -0,0 +1,29 @@
+#include <stdio.h>
+
+/* The C Programming Language, 2nd Edition
+ *
+ * Exercise 1-5: Modify the temperature conversion program to print the table in
+ * reverse order, that is, from 300 degrees to 0.
+ *
+ * Answer: Ensure that fahr starts at upper and the while loop runs until zero.
+ */
+
+int main(void) {
+ float fahr, celsius;
+ int lower, upper, step;
+
+ lower = 0;
+ upper = 300;
+ step = 20;
+
+ fahr = upper;
+
+ printf(" F | C\n");
+ printf("------------\n");
+ while (fahr >= 0) {
+ celsius = (5.0 / 9.0) * (fahr - 32.0);
+ printf(" %3.0f %6.1f\n", fahr, celsius);
+ fahr -= step;
+ }
+ return 0;
+}
diff --git a/1-06_eof-test.c b/1-06_eof-test.c
new file mode 100644
index 0000000..5214338
--- /dev/null
+++ b/1-06_eof-test.c
@@ -0,0 +1,15 @@
+#include <stdio.h>
+
+/* The C Programming Language, 2nd Edition
+ *
+ * Exercise 1-6: Verify that the expression 'getchar() != EOF' is 0 or 1.
+ *
+ * Answer: Easy.
+ */
+
+int main(void) {
+ int c;
+ c = (getchar() != EOF);
+ printf("%d\n", c);
+ return 0;
+}
diff --git a/1-07_eof-value.c b/1-07_eof-value.c
new file mode 100644
index 0000000..aaf838b
--- /dev/null
+++ b/1-07_eof-value.c
@@ -0,0 +1,13 @@
+#include <stdio.h>
+
+/* The C Programming Language, 2nd Edition
+ *
+ * Exercise 1-7: Write a program to print the value of EOF.
+ *
+ * Answer: Just cast it to an integer placeholder in printf().
+ */
+
+int main(void) {
+ printf("%d\n", EOF);
+ return 0;
+}
diff --git a/1-08_space-counter.c b/1-08_space-counter.c
new file mode 100644
index 0000000..0e00176
--- /dev/null
+++ b/1-08_space-counter.c
@@ -0,0 +1,29 @@
+#include <stdio.h>
+
+/* The C Programming Language, 2nd Edition
+ *
+ * Exercise 1-8: Write a program to count blanks, tabs, and newlines.
+ *
+ * Answer: Run a loop with getchar() and check its value. Then add to the
+ * counts and spit them out at the end of the loop.
+ */
+
+int main(void) {
+ char c;
+ int blanks, tabs, nls = 0;
+
+ while ((c = getchar()) != EOF) {
+ if (c == ' ') {
+ blanks++;
+ }
+ if (c == '\t') {
+ tabs++;
+ }
+ if (c == '\n') {
+ nls++;
+ }
+ }
+
+ printf("%d blanks, %d tabs, and %d newlines.\n", blanks, tabs, nls);
+ return 0;
+}
diff --git a/1-09_single-spacing.c b/1-09_single-spacing.c
new file mode 100644
index 0000000..82447ee
--- /dev/null
+++ b/1-09_single-spacing.c
@@ -0,0 +1,27 @@
+#include <stdio.h>
+
+/* The C Programming Language, 2nd Edition
+ *
+ * Exercise 1-9: Write a program to copy its input to its output, replacing each
+ * string of one or more blanks by a single blank.
+ *
+ * Answer: Run a loop with getchar() and check its value. If it's a space, count
+ * it, but prevent further spaces from being printed. Anything else should
+ * simply be spat out.
+ */
+
+int main(void) {
+ char c;
+ int spaces = 0;
+
+ while ((c = getchar()) != EOF) {
+ if (c == ' ' && spaces == 0) {
+ putchar(c);
+ spaces++;
+ } else {
+ putchar(c);
+ }
+ }
+
+ return 0;
+}
diff --git a/1-10_literal-escapes.c b/1-10_literal-escapes.c
new file mode 100644
index 0000000..903fff4
--- /dev/null
+++ b/1-10_literal-escapes.c
@@ -0,0 +1,33 @@
+#include <stdio.h>
+
+/* The C Programming Language, 2nd Edition
+ *
+ * Exercise 1-10: Write a program to copy its input to its output, replacing
+ * each tab by '\t', each backspace by '\b', and each backslash by '\\'. This
+ * makes tabs and backspaces visible in an unambiguous way.
+ *
+ * Answer: Run a loop with getchar() and check its value. When you run into a
+ * tab, backspace, or backslash, just output the two characters and move on.
+ */
+
+int main(void) {
+ char c;
+
+ while ((c = getchar()) != EOF) {
+ if (c == '\t') {
+ printf("\\t");
+ continue;
+ }
+ if (c == '\b') {
+ printf("\\b");
+ continue;
+ }
+ if (c == '\\') {
+ printf("\\\\");
+ continue;
+ }
+ putchar(c);
+ }
+
+ return 0;
+}
diff --git a/1-11_word-count.c b/1-11_word-count.c
new file mode 100644
index 0000000..1b4056c
--- /dev/null
+++ b/1-11_word-count.c
@@ -0,0 +1,37 @@
+#include <stdio.h>
+
+/* The C Programming Language, 2nd Edition
+ *
+ * Exercise 1-11: How would you test the word count program? What kinds of
+ * input are most likely to uncover bugs if there are any?
+ *
+ * Answer: New lines (such as those caused by wrapping text) are most likely to
+ * introduce erroneous word counts, as well as symbols that are strung together
+ * but don't create actual words.
+ */
+
+#define IN 1
+#define OUT 0
+
+int main(void) {
+ int c, nl, nw, nc, state;
+ state = OUT;
+ nl = nw = nc = 0;
+
+ while ((c = getchar()) != EOF) {
+ nc++;
+ if (c == '\n') {
+ nl++;
+ }
+ if (c == ' ' || c == '\n' || c == '\t') {
+ state = OUT;
+ } else if (state == OUT) {
+ state = IN;
+ nw++;
+ }
+ }
+
+ printf("%d %d %d\n", nl, nw, nc);
+
+ return 0;
+}
diff --git a/1-12_one-word-per-line.c b/1-12_one-word-per-line.c
new file mode 100644
index 0000000..3f31d1d
--- /dev/null
+++ b/1-12_one-word-per-line.c
@@ -0,0 +1,39 @@
+#include <stdio.h>
+
+/* The C Programming Language, 2nd Edition
+ *
+ * Exercise 1-12: Write a program that prints its input one word per line.
+ *
+ * Answer: Be sure to output letters when you're in a word, and a newline when
+ * you're out of one.
+ */
+
+#define IN 1
+#define OUT 0
+
+int main(void) {
+ int c, nl, nw, nc, state;
+ state = OUT;
+ nl = nw = nc = 0;
+
+ while ((c = getchar()) != EOF) {
+ nc++;
+ if (c == '\n') {
+ nl++;
+ }
+ if (c == ' ' || c == '\n' || c == '\t') {
+ state = OUT;
+ putchar('\n');
+ } else if (state == OUT) {
+ state = IN;
+ nw++;
+ }
+ if (state == IN) {
+ putchar(c);
+ }
+ }
+
+ printf("%d %d %d\n", nl, nw, nc);
+
+ return 0;
+}