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authorzlg <zlg@zlg.space>2013-02-28 00:03:30 -0600
committerzlg <zlg@zlg.space>2013-02-28 00:03:30 -0600
commitd6e0262ddbbbea7d207631a7889bb2e83a11d79d (patch)
treed53e282f41a96a94edb00d2ba5b1a3fa755c2e06 /ch2
parentSolve Exercise 2-02: No logical operators (diff)
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Change 2-02's solution to a while loop
A recursive function is a bit much for something that simple.
Diffstat (limited to 'ch2')
-rw-r--r--ch2/2-02_no-logical-operators.c18
1 files changed, 7 insertions, 11 deletions
diff --git a/ch2/2-02_no-logical-operators.c b/ch2/2-02_no-logical-operators.c
index 6fea5d6..6fa1601 100644
--- a/ch2/2-02_no-logical-operators.c
+++ b/ch2/2-02_no-logical-operators.c
@@ -9,8 +9,9 @@
*
* for (i=0; i < lim - 1 && (c = getchar()) != '\n' && c != EOF)
* i++;
+ * )
*
- * Answer: A recursive function should do the job. I think...
+ * Answer: A while loop and a few 'if's should do it.
*
*/
@@ -20,25 +21,20 @@ char test[LIMIT] = "";
int i = 0;
int c;
-void save_string(char s[]) {
- if (i < LIMIT - 1) {
+int main() {
+ while (i < LIMIT - 1) {
c = getchar();
if (c != '\n') {
if (c != EOF) {
- s[i] = c;
+ test[i] = c;
i++;
} else {
- return;
+ break;
}
} else {
- return;
+ break;
}
- save_string(s);
}
-}
-
-int main() {
- save_string(test);
printf("%s\n", test);
return 0;
}