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author | Isa Hassen <hassen.isa@gmail.com> | 2015-12-18 19:40:12 -0500 |
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committer | zlg <zlg@zlg.space> | 2015-12-19 17:43:20 -0800 |
commit | 032b64e37a23541e136dcf082a4564023579ed39 (patch) | |
tree | 25d4aa1bab0316ed9fc28f353bb1b38d5e02cc87 /ch1 | |
parent | Solve Exercise 7-1: `upper` and `lower` (diff) | |
download | knr-032b64e37a23541e136dcf082a4564023579ed39.tar.gz knr-032b64e37a23541e136dcf082a4564023579ed39.tar.bz2 knr-032b64e37a23541e136dcf082a4564023579ed39.tar.xz knr-032b64e37a23541e136dcf082a4564023579ed39.zip |
Re-solve Exercise 1-16: arbitrarily long maxline
A completely rewritten solution which follows the spec given in the book
exactly; make the program work for arbitrarily long input lines while
modifying `main()` only. I've only changed the name of the macro MAXLINE
to BUFFSIZE for clarity - otherwise the code is typed up exactly as
found in the book.
It demonstrates the use of a buffer without modifying any of the helper
functions.
Diffstat (limited to 'ch1')
-rw-r--r-- | ch1/1-16_longest-line.c | 104 |
1 files changed, 60 insertions, 44 deletions
diff --git a/ch1/1-16_longest-line.c b/ch1/1-16_longest-line.c index 137bb11..450d990 100644 --- a/ch1/1-16_longest-line.c +++ b/ch1/1-16_longest-line.c @@ -9,55 +9,71 @@ * Answer: The key to arbitrary limits is buffering. Using a buffer allows you * to tackle a problem in chunks of memory instead of all at once. It's * slightly more complicated, but adds usefulness to a program. + * + * This solution, which was contributed by Isa (ibnIrshad), follows the spec + * exactly, by only modifying main(), unlike many other solutions on the + * internet. + * + * Assumptions: + * 1. "arbitrarily long" is interpreted to mean upto the maximum size of an + * integer on the given architechture, e.g. 2^32 unsigned on a 32-bit machine. + * Indeed a string of that size would be larger than 4 gigabytes. + * It is possible to deal with numbers larger than that, but it involves a great + * deal of work abstracting away the concept of an integer, similar to + * dynamically sized arrays. + * + * 2. EOF signal (Ctrl-D) must be given on an empty line */ +#define BUFFSIZE 5 /* renamed MAXLINE and reduced it to 5 to demonstrate +we can handle lines much greater than this number*/ + +int getlinelen(char line[], int maxline); +void copy(char to[], char from[]); + +/* print longest input line */ +main() +{ + /* len of current line, max len seen so far, templen of buffer */ + int len, max, templen; + char buffer[BUFFSIZE]; -#define MAXLENGTH 100 - -int get_line(char s[], int lim) { - /* Put as much as possible into a temp string, and count its length */ - int c, i; - - for (i = 0; i < lim && (c = getchar()) != EOF && c != '\n'; ++i) { - s[i] = c; - } - if (c == '\n') { - s[i] = c; - ++i; - } - s[i] = '\0'; - return i; + max = len = 0; + + while ((templen = getlinelen(buffer, BUFFSIZE)) > 0) { + len += templen; + + if (buffer[templen-1] == '\n'){ + if (len > max) + max = len; + len = 0; + } + } + printf("\nLen of longest line: %d\n", max); + return 0; } -void copy(char from[], char to[]) { - int i = 0; +/* getlinelen: read a line into s, return length */ +int getlinelen(char s[], int lim) +{ + int c, i; - while ((to[i] = from[i]) != '\0') { - ++i; - } + for (i=0; i<lim-1 && (c=getchar()) != EOF && c!='\n'; ++i) + s[i] = c; + if (c == '\n') { + s[i] = c; + ++i; + } + s[i] = '\0'; + return i; } -int main() { - int len, max; - - char line[MAXLENGTH]; - char longest[MAXLENGTH]; - - max = 0; - while ((len = get_line(line, MAXLENGTH)) > 0) { - if (len > max) { - max = len; - copy(line, longest); - } - } - - printf("\nThe longest line is %3d characters long.\n", max); - printf("----------------------------------------\n"); - if (max > 0) { - printf("%-s", longest); - if (max == MAXLENGTH && longest[max - 1] != '\n') { - printf("\n"); - } - } - - return 0; + +/* copy: copy 'from into 'to'; assume to is big enough */ +void copy(char to[], char from[]) +{ + int i; + + i = 0; + while ((to[i] = from[i]) != '\0') + ++i; } |