diff options
Diffstat (limited to 'ch5')
-rw-r--r-- | ch5/5-09_yearday-pointers.c | 74 |
1 files changed, 74 insertions, 0 deletions
diff --git a/ch5/5-09_yearday-pointers.c b/ch5/5-09_yearday-pointers.c new file mode 100644 index 0000000..7a28f88 --- /dev/null +++ b/ch5/5-09_yearday-pointers.c @@ -0,0 +1,74 @@ +#include <stdio.h> + +/* The C Programming Language: 2nd Edition + * + * Exercise 5-9: Rewrite the routines day_of_year() and month_day() with + * pointers instead of indexing. + */ + +static char daytab[] = { + 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 +}; + +int day_of_year(int year, int month, int day); +void month_day(int year, int yearday, int *pmonth, int *pday); + +int main() { + int i, m, d, doy; + int tvals[][4] = { + { 2012, 2, 29, 60 }, + { 2013, 3, 1, 60 }, + { 1985, 10, 22, 295 } + }; + m = d = 0; + doy = 0; + + // It said nothing about avoiding indexing in main()! + for (i = 0; i < 3; i++) { + doy = day_of_year(tvals[i][0], tvals[i][1], tvals[i][2]); + month_day(tvals[i][0], doy, &m, &d); + if (doy > 0 && m != 0 && d != 0) { + printf("%4d-%02d-%02d is day %3d of the year. ", tvals[i][0], tvals[i][1], tvals[i][2], doy); + printf("Day %3d of %4d is month %2d and day %3d.\n", doy, tvals[i][0], m, d); + } else { + printf("Out of range\n"); + } + } + return 0; +} + +int day_of_year(int year, int month, int day) { + int i, leap; + leap = (year % 4 == 0 && year % 100 != 0) || year % 400 == 0; + + if (month < 1 || month > 12) { + return -1; + } + // Slightly complicated pointer math is needed to account for leap years + if (day > *(daytab + month) + ((month == 2) ? leap : 0) || day < 1) { + return -1; + } + for (i = 1; i < month; i++) { + // here, too + day += *(daytab + i) + ((i ==2) ? leap : 0); + } + return day; +} + +void month_day(int year, int yearday, int *pmonth, int *pday) { + int i, leap; + leap = (year % 4 == 0 && year % 100 != 0) || year % 400 == 0; + + if (yearday > 365 + leap || yearday < 1) { + *pmonth = 0; + *pday = 0; + return; + } + // ...and here. :P + for (i = 1; yearday > *(daytab + i) + ((i == 2) ? leap : 0); i++) { + yearday -= *(daytab + i) + ((i == 2) ? leap : 0); + } + *pmonth = i; + *pday = yearday; +} + |