1 files changed, 0 insertions, 48 deletions
diff --git a/1-20_detab.c b/1-20_detab.c
deleted file mode 100644
index dc8f5b5..0000000
--- a/1-20_detab.c
+++ /dev/null
@@ -1,48 +0,0 @@
-#include <stdio.h>
-
-/* The C Programming Language: 2nd Edition
- * Exercise 1-20:
- * "Write a program `detab` that replaces tabs in the input with the proper
- * number of blanks to space to the next tabstop. Assume a fixed set of
- * tabstops, say every 'n' columns. Should 'n' be a variable or a symbolic
- * parameter?"
- *
- * Answer: 'n' should be a symbolic parameter. It's more apparent what's being
- * worked with and it's not susceptible to scope. Though, in this simple
- * program it really doesn't matter.
- *
- * The "correct" solution uses the isprint() stdlib function, but it's not
- * covered by this point in the book, so I did not use it.
- */
-
-#define TABWIDTH 8
-
-int main(void) {
-	int column, c;
-	column = 0;
-	while ((c = getchar()) != EOF) {
-		// Be sure that the character is a tab
-		if (c == '\t') {
-			/*
-			 * Divide a line by TABWIDTH and you have your tabstops. If you
-			 * modulo by TABWIDTH and it equals 0, you've reached a tabstop and
-			 * don't need to output more spaces!
-			 */
-			while (column % TABWIDTH != 0 && column != 0) {
-				putchar(' ');
-				++column;
-			}
-		} else {
-			if (c == '\n') {
-				// Line-endings should reset the column counter after being output.
-				putchar(c);
-				column = 0;
-			} else {
-				// Now we can just output and increase column!
-				putchar(c);
-				++column;
-			}
-		}
-	}
-	return 0;
-}