Solve Exercise 2-02: No logical operators

The text doesn't specify which technique to use. The section outlined
operator precedence, but I couldn't think of a way to check for truth in
the three main expressions without logical operators. So I turned to a
recursive function. It works, but I'm not sure if it's what K&R were
after.

1 files changed, 44 insertions, 0 deletions

diff --git a/ch2/2-02_no-logical-operators.c b/ch2/2-02_no-logical-operators.c
new file mode 100644
index 0000000..6fea5d6
--- /dev/null
+++ b/ch2/2-02_no-logical-operators.c
@@ -0,0 +1,44 @@
+#include <stdio.h>
+
+/* The C Programming Language, 2nd Edition
+ *
+ * Exercise 2-2: Write a loop equivalent to the 'for' loop above without
+ * using && or ||.
+ *
+ * (The for loop is:
+ *
+ * for (i=0; i < lim - 1 && (c = getchar()) != '\n' && c != EOF)
+ *     i++;
+ *
+ * Answer: A recursive function should do the job. I think...
+ *
+ */
+
+#define LIMIT 17
+
+char test[LIMIT] = "";
+int i = 0;
+int c;
+
+void save_string(char s[]) {
+	if (i < LIMIT - 1) {
+		c = getchar();
+		if (c != '\n') {
+			if (c != EOF) {
+				s[i] = c;
+				i++;
+			} else {
+				return;
+			}
+		} else {
+			return;
+		}
+		save_string(s);
+	}
+}
+
+int main() {
+	save_string(test);
+	printf("%s\n", test);
+	return 0;
+}