Solve Exercise 2-10: lower()

Also added more information to 2-09's comments.

1 files changed, 20 insertions, 0 deletions

diff --git a/ch2/2-10_lower.c b/ch2/2-10_lower.c
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+#include <stdio.h>
+
+/* The C Programming Language: 2nd Edition
+ *
+ * Exercise 2-10: Rewrite the function 'lower', which converts upper case
+ * letters to lower case, with a conditional expression instead of if-else.
+ *
+ * Answer: The tertiary ?: operators also _evaluate_, so they can be used in
+ * a lot of different places.
+ */
+
+int lower(int c) {
+	return (c >= 'A' && c <= 'Z') ? c + 'a' - 'A' : c;
+}
+
+int main() {
+	char foo = 'F';
+	printf("The follow letter should be lowercase: %c\n", lower(foo));
+	return 0;
+}