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| author | zlg <zlg@zlg.space> | 2015-12-05 21:46:57 -0800 |
|---|---|---|
| committer | zlg <zlg@zlg.space> | 2015-12-05 21:46:57 -0800 |
| commit | 45b8159cc39792ddc4e989b11036f026d49f33e7 (patch) | |
| tree | 08efc8f468ff8c3461fc32735b7d4423c9def272 /ch2/2-03_hex-to-int.c | |
| parent | Solve Exercise 6-5: undef() (diff) | |
| download | knr-45b8159cc39792ddc4e989b11036f026d49f33e7.tar.gz knr-45b8159cc39792ddc4e989b11036f026d49f33e7.tar.bz2 knr-45b8159cc39792ddc4e989b11036f026d49f33e7.tar.xz knr-45b8159cc39792ddc4e989b11036f026d49f33e7.zip | |
Solve Exercise 6-6: A simple `#define` processor
This exercise is probably the most challenging "function puzzle" thus
far. Modifying getword(), using various states, and the hashtable all
create an example of how small building blocks can work together to
make something.
The implementation is very simple and nowhere near completely supporting
'#define', but that's not the point. To properly support it, you'd need
to build an entire preprocessor/parser, and that's far beyond the scope
of both the exercise and book.
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